4y-(1/x^2)

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Solution for 4y-(1/x^2) equation: 


D( x )

x^2 = 0

x^2 = 0

x^2 = 0

1*x^2 = 0 // : 1

x^2 = 0

x = 0

x in (-oo:0) U (0:+oo)

4*y-(1/(x^2)) = 0

4*y-x^-2 = 0

-1*x^-2 = -(4*y) // : -1

x^-2 = 4*y

-2 < 0

1/(x^2) = 4*y // * x^2

1 = 4*x^2*y // : 4*y

1/(4*y) = x^2

x^2 = 1/(4*y) // ^ 1/2

abs(x) = 1/(2*y^(1/2))

x = 1/(2*y^(1/2)) or x = -(1/(2*y^(1/2)))

x in { 1/(2*y^(1/2)), -(1/(2*y^(1/2))) }

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